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Partial complements in finite soluble groups

Chen, Ingrid

Description

Let G be a finite group with normal subgroup N. Let K be a subgroup of G. We say that K is a partial complement of N in G if N and K intersect trivially. There are two main results in this work. The first main result arises from analysing when each partial complement of N in G is contained in a complement of N in G when G is a finite soluble group, N is the product of minimal normal subgroups, N is complemented and all the complements of N in G are conjugate. We show that each partial...[Show more]

dc.contributor.authorChen, Ingrid
dc.date.accessioned2018-11-22T00:03:50Z
dc.date.available2018-11-22T00:03:50Z
dc.date.copyright2012
dc.identifier.otherb3095374
dc.identifier.urihttp://hdl.handle.net/1885/149677
dc.description.abstractLet G be a finite group with normal subgroup N. Let K be a subgroup of G. We say that K is a partial complement of N in G if N and K intersect trivially. There are two main results in this work. The first main result arises from analysing when each partial complement of N in G is contained in a complement of N in G when G is a finite soluble group, N is the product of minimal normal subgroups, N is complemented and all the complements of N in G are conjugate. We show that each partial complement of N in G is contained in a complement of N in G if and only if N is projective. The next natural question is: if N is non-projective, which partial complements are contained in a complement of N in G? We say that a cyclic p-partial complement is a partial complement that is cyclic and its order is a power of p. We establish exactly which cyclic p-partial complements are contained in a conjugate of H. So the next question is: if the partial complement is a non-cyclic p-partial complement, how do we know that is contained in a conjugate of H? This is a difficult question and because of restriction on representation theory, we have needed to restrict H to be in the class of groups that are nilpotent p'-groups by p-groups. To answer this question, we use the first cohomology group. The first cohomology group is the number of conjugacy classes of complements to N in G. That is, if we have a partial complement K such that the first cohomology group vanishes then we know there is only one conjugacy class of complements of N in NK and therefore K is in a conjugate of H. The second main result finds exactly when the first cohomology group vanishes. This is a sufficient condition for a partial complement to be contained in a complement of N in G. -- provided by Candidate.
dc.format.extentiv, 86 leaves.
dc.language.isoen_AU
dc.rightsAuthor retains copyright
dc.subject.lccQA177.C54 2012
dc.subject.lcshFinite groups
dc.subject.lcshSolvable groups
dc.titlePartial complements in finite soluble groups
dc.typeThesis (PhD)
local.description.notesThesis (Ph.D.)--Australian National University
dc.date.issued2012
local.type.statusAccepted Version
local.contributor.affiliationAustralian National University
local.identifier.doi10.25911/5d5e70e804d17
dc.date.updated2018-11-20T01:33:18Z
dcterms.accessRightsOpen Access
local.mintdoimint
CollectionsOpen Access Theses

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